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Posted by on July 24, 2008, 10:09 am
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I need to bend some 6061T6 .040 aluminum that is a U shape, 8" wide
with 2" legs. I wanted to know if I mark exactly the 8" and make the
bend will the radius cause the overall width to be less or more than
the 8". I dont want to waste material by trying to bend 8" width and
then the overall width is either 7 7/8" or 8 1/8", any suggestions?
Thanks,
Mike
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Posted by Randy Replogle on July 24, 2008, 12:01 pm
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mfrancis3@tx.rr.com wrote:
> I need to bend some 6061T6 .040 aluminum that is a U shape, 8" wide
> with 2" legs. I wanted to know if I mark exactly the 8" and make the
> bend will the radius cause the overall width to be less or more than
> the 8". I dont want to waste material by trying to bend 8" width and
> then the overall width is either 7 7/8" or 8 1/8", any suggestions?
> Thanks,
> Mike
More than 8" by the amount of the thicknesses of the two legs and part
of whatever radius is in the corners.
Also 6061-T6 might crack. Use T0 or T4, i's "softer".
RR
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Posted by Grant Erwin on July 24, 2008, 12:34 pm
Please log in for more thread options mfrancis3@tx.rr.com wrote:
> I need to bend some 6061T6 .040 aluminum that is a U shape, 8" wide
> with 2" legs. I wanted to know if I mark exactly the 8" and make the
> bend will the radius cause the overall width to be less or more than
> the 8". I dont want to waste material by trying to bend 8" width and
> then the overall width is either 7 7/8" or 8 1/8", any suggestions?
> Thanks,
> Mike
You need to search on bending allowance. I archived this from this NG a
long time ago:
For 90 deg bends in cold rolled steel the following works well for me:- L=
(0.71xT)+(1.57xR) Where L=length of stock for each bend. T=material thickness
R= inside radius of bend. For hot rolled substitute (0.64xT) for (0.71xT) The
eight times rule is that a vee width of eight times material thickness will
give you an inside bend radius equal to the material thickness.
I would be somewhat concerned about cracking on T6 heat treated 6061. Maybe
you should anneal the material in the bend areas?
Grant
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Posted by Leo Lichtman on July 24, 2008, 12:42 pm
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8" width and
> then the overall width is either 7 7/8" or 8 1/8", any suggestions?
^^^^^^^^^^^^^^^^^^^
Yes. Do a few test strips. That's not "waste." That's *planning.*
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Posted by Errol Groff on July 24, 2008, 1:05 pm
Please log in for more thread options On Thu, 24 Jul 2008 07:09:02 -0700 (PDT), mfrancis3@tx.rr.com wrote:
>I need to bend some 6061T6 .040 aluminum that is a U shape, 8" wide
>with 2" legs. I wanted to know if I mark exactly the 8" and make the
>bend will the radius cause the overall width to be less or more than
>the 8". I dont want to waste material by trying to bend 8" width and
>then the overall width is either 7 7/8" or 8 1/8", any suggestions?
>Thanks,
>Mike
Take a look at these these resourses.
http://neme-s.org/dave_bono.htm
http://neme-s.org/images/PDF%20Files/bending.pdf
Errol Groff
Instructor, Machine Tool Department
H.H. Ellis Technical High School
Danielson, CT
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> with 2" legs. I wanted to know if I mark exactly the 8" and make the
> bend will the radius cause the overall width to be less or more than
> the 8". I dont want to waste material by trying to bend 8" width and
> then the overall width is either 7 7/8" or 8 1/8", any suggestions?
> Thanks,
> Mike