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Posted by Karl Townsend on June 11, 2009, 11:05 pm
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I'm trying to decide how large a roller chain I need...
Does anyone know of a table that shows how much each size roller chain
stretches under increasing loads?
The application is my plasma table. I'm upgrading from cable tension drive
to roller chain.
Karl
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Posted by Pete C. on June 11, 2009, 11:13 pm
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Karl Townsend wrote:
>
> I'm trying to decide how large a roller chain I need...
>
> Does anyone know of a table that shows how much each size roller chain
> stretches under increasing loads?
>
> The application is my plasma table. I'm upgrading from cable tension drive
> to roller chain.
>
> Karl
Rack and pinion drive is the most common / popular for most plasma
tables. Plenty of sources out there for the components and plenty of
info on CNCZONE.
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Posted by Karl Townsend on June 11, 2009, 11:32 pm
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> Rack and pinion drive is the most common / popular for most plasma
> tables. Plenty of sources out there for the components and plenty of
> info on CNCZONE.
Yea, I spend more time over there than here. rack pinion is best but I'm
refitting an existing machine with a clever cable drive. Won't be a big
deal to replace pulleys with sprockets and cable with chain.
lots of machines have been built with roller cahin drive over there also.
But, no sign of mechanical design for chain size.
Karl
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Posted by Ned Simmons on June 11, 2009, 11:57 pm
Please log in for more thread options On Thu, 11 Jun 2009 22:05:03 -0500, "Karl Townsend"
>I'm trying to decide how large a roller chain I need...
>
>Does anyone know of a table that shows how much each size roller chain
>stretches under increasing loads?
>
The chain mfrs list the maximum allowable tension for low speed
drives, but I don't recall ever seeing tabulated values for the
"stretchiness" of chain. It'd be easy enough to estimate by treating
the sideplates as a solid strip.
For example, the sideplates of #40 chain are .059 x .472.
.059 x .472 x 2 = .05 in^2
Young's modulus, stress over strain = 30E6 (lb/in2)/(in/in) for steel
.05 in^2 x 30E6 (lb/in2)/(in/in)) = 1.5E6 lb (in/in)
In other words, if you had an imaginary chain made of steel with
infinite yield strength, 1.5 million pounds would stretch a length of
#40 chain to twice its original length. In other, other words, a 100
inch length of real #40 chain will stretch about .007" under a 100#
load.
--
Ned Simmons
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Posted by Ned Simmons on June 12, 2009, 12:04 am
Please log in for more thread options wrote:
>On Thu, 11 Jun 2009 22:05:03 -0500, "Karl Townsend"
>
>>I'm trying to decide how large a roller chain I need...
BTW, you can find this data on steel corded timing belts, if you want
to compare. The metric AT profile belts are generally stiffer and
stronger than the trapezoidal toothed belts. I know Breco, for one,
has this data in their catalogs.
--
Ned Simmons
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> I'm trying to decide how large a roller chain I need...
>
> Does anyone know of a table that shows how much each size roller chain
> stretches under increasing loads?
>
> The application is my plasma table. I'm upgrading from cable tension drive
> to roller chain.
>
> Karl